First of all, you have to recite dozens of formulas. In fact, it can also be reversed.

1, which is the integral formula ∫( 1/x? ) dx =-1/x, and the inverse formula is: (1/x)' =-1/x? Conversely, 1/x? Integral of =- 1/x

? ∫( 1/x)dx=lnx, whereas (lnx)' = 1/x, the constant terms of all terms can be outside.

So the second small question: the original formula =∫( 1→2)3/x? dx+∫( 1→2)2/xdx =( 1→2)|？ (﹣3/x)+( 1→2)|？ (2lnx)

=3/2+2ln2。

2. In the same way, ∫ 1/x=lnx, but x√x(x times the root sign) can be transformed into the third power of x.

So the original simplification is the answer to your 10 question.

Hey, my word is a cracked version of the unsigned editing component. I don't know if you can understand.

There are many mathematical formulas in this link below. I hope it helps you. You should recite the formula.

/view/3 e 2 CD 4 eab 8 f 67 c 1 cfad 6b 8 cf . html

You are so strong. You study integral in your sophomore year, and we only learn it in our freshman year. . .