Two cars, A and B, leave from A and B relatively at the same time and meet in four hours. After the meeting, car A will arrive in B in three hours. If car A is 20 kilometers faster than car B per hour, how many meters is there between A and B?

Solution: It takes 4+3=7 hours for a car to travel all the way.

In other words, when they met, A walked 4/7 of the whole journey.

Then B walked 3/7 of the way.

Speed ratio of Party A and Party B = distance ratio = 4/7: 3/7 = 4: 3 = 1: 3/4.

So the speed of a car = 20/(1-3/4) = 80 km/h.

AB Distance =80×7=560 km

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