There is a feeding bottle, the upper part of which is cylindrical, and its height is 3 ∕ 4 of the whole bottle height, and its lower part is irregular, accounting for 1∕4 of the bottle height. Now there is only some milk left in the bottle. How to determine the percentage of milk in the whole bottle with a ruler without opening the bottle cap?

Turn the bottle upside down, the highest point of milk is on the cylinder.

See if this is right;

Let: cylinder volume V 1, height 3/4*H, bottom area s;

Irregular volume V2, height 1/4*H 。

The highest point of the bottle is from the "top" of the garden X 1, and the highest point of the bottle is from the "bottom" of the garden X2.

Therefore, there is milk.

Forward: (3/4*H-X 1)*S+V2

Inverted: X2

Q: (X2*S)/(V 1+V2)

=(X2 * seconds) /(3/4 * hours * seconds +V2)

=(X2 * S)/(3/4 * H * S+X2 * S-(3/4 * H-x 1)* S)

=(X2)/(3/4*H+X2-3/4*H+X 1)

=X2/(X 1+X2)