The value of 2.2. SXB will not exceed (250 * 999+999)/2005 =125.06, so we can determine that S= 1, X=2, B.
3. The unit number of the left result is Z, and the unit number of the right result is either 0 or 5, so when Z=0 is 5 and Z=0, B must be even, and when Z=5, B is odd, so B cannot be 0; So the value of b is 3, 4 and 5.
4. The maximum value on the right is 2005 *125 = 250625; The minimum value is 2005 *123 = 246615;
The value of 5.5. HKT will not be less than (2466 15-999)/250=982.464, so H=9, K=8, t >;; =3, the maximum value of HKT is 987 and the minimum value is 983;
6. Suppose Z=0, then B=4, then the right side =2005* 124=248620, then the minimum value of ASZ is 248620-250*987= 1870, which does not meet the conditions, then Z=5, then B can only = 3.
7. The current formula is 250 * 98t+a15 = 2005 *123 = 246615; The values of a and t may be 4,6,7, so the maximum value of 98T is (246615-415)/250 = 984.8, so t can only be equal to 4. When t =4, A 15 = 246 18.
8. So, H=9, K=8, T=4, A=6, S= 1, Z=5, X=2, B=3, so "good classroom mathematics" =HKTASZ=9846 15.