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An application problem in the math test of junior high school in 2009 in Luzhou Tian Li International School 20 1 1- review guide for junior high school.
Solution: Let the height of residual liquid be H, the bottom radius of residual liquid be R, the height of container be H, and the bottom radius of container be R..

C is the midpoint of AB.

BC/AB=h/H=r/H= 1/2

Container volume V/ liquid volume v = (1/3 * pie * r * h)/(1/3 * pie * r * h) = 8.

Effluent liquid: 250*(8- 1)= 1750 (g)

Answer: The liquid outflow is 1750g. ?

Explanation: As long as the volume ratio of the remaining solution to the original container is found out, according to this ratio, the volume of the remaining solution is 1 serving, the volume of the container is 8, and 7 portions have been drained, each weighing 250g, so how much liquid has flowed out can be found out.