Therefore, when x= 1, the function f(x) gets the maximum value of 2...5 points.

(2) press f (x) >; | x-a | ≥ 4 | x- 1 | 0,

Square of both sides: (x-a) 2 ≥ 4 (x- 1),

That is 3x2+2 (a-4) x+4-a 2 ≤ 0,? ..... 7 points

Get (x-(2-a)) (3x-(2+a)) ≤ 0，

Therefore, ① when a> is 1, the solution set of inequality is (2-a,);

② When a = 1, the solution set of inequality is {x | x =1};

③ when a

leave out