The naming process of a complex number is to multiply the denominator by a factor so that the denominator satisfies the square difference formula, so that I? A that removes the item that contains i.
5(4+i)？ /i(2+i) Simplify the numerator and denominator first.
=5( 16+8i- 1)/i(2+i)
The denominator of =5( 15+8i)/(- 1+2i) is multiplied by (-1-2i) at the same time, so that the denominator satisfies the square difference formula and I is eliminated.
= 5( 15+8i)(- 1-2i)/(- 1+2i)(- 1-2i)
= 5(- 15-8i-30i+ 16)/( 1+4)
=5( 1-38i)/5
= 1-38i
So the result of simplification is:
5(4+i)？ /i(2+i) = 1-38i
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