(1)E and f are the midpoint of DP and DC, respectively, so EF equals half CP equals 3, GF equals AD equals 12, so EF ratio EG=3/(3+ 12)= 1/5. Because FM is parallel to GN, the triangle e FM is similar to the triangle EGN.

(2) If M is MQ, the parallel AD intersects with AN at Q, ∠ DEG+∠ GEN = ∠ GED+∠ CAP = 90, so ∠gen=∠cap is parallel to ∠qmn=∠cap and ∠. So equal.