The symmetry axis is on the right side of the Y axis, and the left and right sides are different, so b >；; 0,

The intersection of the image and the y axis is on the positive semi-axis, so c >: 0.

So ABC

When x=- 1 and y=a-b+c, it can be seen from the figure that y < 0, so a+c.

When x= 1, y=a+b+c, as can be seen from the figure, y >；; 0, so a+b a+b+c & gt；; 0, correct

When x=- 1, a-b+c < 0 and vertex abscissa -b /2a = 1, a=-b/2 and a-b+c can be obtained.

-b/2–b+ c & lt。 0 and 2c