Looking closely, only A and E will produce single digits, but obviously A and E can't be 0, because the single digits of the number obtained by E*4 are equal to A.

If E= 1, A=4, if E=2, A=8, if E=3, A=2, if E=4, A=6, if E=6, A=4, E=7, A=8, E=8, A=2.

Because ABCDE and EDCBA are both five digits with no carry, so A can only be less than E and less than 2.5, then A=2 and E=8 can be obtained.

Similarly, there is no carry relationship between b and d, and B*4+3=D, then obviously, b < D, B= 1, D=7,

Finally, bring it into the operation and you can get C=9.

So the answer is 2 1978*4=879 12.

I've been thinking about it for a long time. I hope you can adopt it!