Because CO shares ∠AOD, ∠COE=∠COB 1,
Because △ABC is folded along AC to get △ACB 1, △ ABC △ ACB1.
So ∠ CB 1o = ∠ ABC = ∠ CEO = 90, CB 1=CB.
Add CO=CO to get △ Coe△ cob1,
So CB 1=CD.
Let the coordinate of C be (a, 2/a), then CB=CB 1=CD=2/a, and the coordinate of B is (a, 4/a).
So the ordinate of a is 4/a, and the coordinates of a (a/2, 4/a) are obtained.
S△cob 1 = S△COD = 1/2 * a *(2/a)= 1
S△ACB 1 = S△ABC = 1/2 *(a-a/2)*(4/a-2/a)= 1/2
So the area of the quadrilateral OABC = 1+ 1/2*2=2.