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Mathematics is really an interesting math problem.
Because the product is six identical numbers, according to the principle of 7 *1* 13 =1001,the product must be a multiple of 7, 1 1 and/kloc-0.

Six identical numbers must be multiples of11,1 1 1 = 37 * 3, so the product must be multiples of 3 and 37. So the grade must be a multiple of 3,7, 1 1,13,37. The multiplicand is multi-digit and the multiplier is single-digit, so the multiplier (number) can only be 3 or 7.

If the number =3, then 30000~40000, *3 can only be the first six digits of 1. Once this happens, the unit of multiplicand-interest will be unqualified.

So the number can only be 7.

At this time, because the product can only be all 5. Otherwise 7*7=49. There are different numbers.

So the product should be 555555. The original five digits can only be 555555/7=79365.