mgsin37？ L-μmgs=0
Obtaining the dynamic friction coefficient between the small slider and the horizontal plane
μ=mgsin37？ Lmgs=2435。
(2) The small slider moves from A to C, which is obtained by kinetic energy theorem.
Fs-μmgs+Fx-mgsin37？ L=0
Solution: When the small slider moves on the inclined plane, the distance of pulling force is x =1.25m. 。
(3) When the slider moves from A to B, according to the kinetic energy theorem, Fs-μmgs= 12mv2,
According to Newton's second law, f-F-mgsin37 =ma.
According to the kinematic formula, x=vt+ 12at2,
The simultaneous solution shows that when the small slider moves on the inclined plane, the time of pulling force is t = 0.5s
Answer: (1) The dynamic friction coefficient between the small slider and the horizontal plane is 2435.
(2) When the small slider moves on the inclined plane, the pulling distance is1.25m. 。
(3) When the small slider moves on the inclined plane, the pulling time is 0.5s