Mr. Li bought an apartment in early 2008 and sold it for $3.2 million at the end of 2008. Suppose the price of this apartment dropped by 35% from 65438+ 10 to 65438+ 10, and increased by 10% every month from 165438+ 10 to the end of the year.

(1) Ask Mr. Li to pay the total price of the apartment to the nearest 10000 USD.

(2) Find the annual price change rate of this apartment in 2008, and keep two significant figures.

(Translated for reference)

Since you are a junior high school student, you must know the equation!

Solution: (1) Suppose that the total price paid by Mr. Li to buy this apartment is $ X.

x( 1-35%)( 1+ 10%)？ =3200000,

That is, 0.65×1.21x = 3,200,000, 0.7865x=3200000, x = 3,200,000 ÷ 0.7865 and x ≈ 4,070,000.

(2)(4070000-3200000)÷4070000

=870000÷4070000

≈0.2 1=2 1%