It is known that the power function y=(t3-t+ 1)x to the power of 0.2(7+3t-2t2) t∈Z is an even function, which is the value of increasing function's finding t in the interval (0, +∞).

Answer: Your function should be: y = (t 3-t+1) x (0.2 (7+3t-2t2).

Where t 3-t+ 1 is a coefficient and 0.2 (7+3t-2t 2) is an exponent.

The exponent is required to be greater than zero and even. 7+3t-2t^2>； 0, the solution is: (√ 65-3)/4.

Because 9 & gt√65 & gt；; 8, so 1

At this time, t 3-t+ 1 = 7. Meet the requirements of the problem.

t=2