Eat two, and there is one left; Go three, turn left two; Take six steps, and the remaining five steps should be the common multiple of 2, 3 and 6 minus 1, that is, 12k- 1, where k is an arbitrary positive integer, and take seven steps, that is, 12k- 1 can be integer by 7 and 65438+. So 5k- 1 can be divisible by 7. Obviously, the smallest k is k=3 and the number of steps is 12*3- 1=35. Because k is not unique, the number of steps that meet the conditions is not unique. Calculate all the numbers that can make 12k- 1 divisible by 7.