Current location - Training Enrollment Network - Mathematics courses - Mathematical model problem
Mathematical model problem
How many days are there in 20 12? 20 12/4=503, which is 366 days in leap year.

If you buy all five kinds of goods, you can wear at most 5*5*5*5=625 patterns.

Things you buy must be able to wear patterns above 366. There are only 5*5*5*3=375 species or 5*5*4*4=400 species. There are both schemes, and 5*5*5*4=500 patterns are obviously wasted, and it is even more wasteful to buy them all.

5, 5, 5, 3 and 5, 5, 4, 4 have one thing in common, that is, out of 20 items (four kinds, five styles each), two items are missing.

Obviously, there is no need to buy the most expensive two (of course, the choice of these two also needs to be combined with the preferential margin), so there is no need to buy 559 and 659. Buy another one.

So the calculated price is as follows:

Hat = 40+58+80+168+235 = 581,and returns 5*30= 150, making a total of 581-kloc-0/50 = 43/kloc-.

Coat =188+240+356+212+150 =1046,1046 * 0.88 * 0.88 = 81.

Pants = 70+120+130+190+210 = 720,720 * 0.75 = 540.

Shoes = 199+300+400, 300 is 30% off, 400 is 40% off, 199+300*0.7+400*0.6=649.

Total = 431+810.0224+540+649 = 2430.0224 yuan.