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A problem of compulsory four in senior high school mathematics
Solution: (1)∵ the highest point M(2, √2)

∴ Yi Zhi A = √ 2

∫Q(6,0)

∴ 1/4T=6-2=4 ∴T= 16

∴ω=2π/T=π/8

∴ Substitute (6,0) into f (x) = √ 2sin (π/8x+φ) to get φ = π/4.

(2)∴f(x)=√2sin(π/8x+π/4)

F(x)=g(x-8)

∴g(x)=√2sin(π/8x-3π/4)

Don't know right