First question: First, use y=x2 and y=x to find the coordinates of the intersection, where x=0 and x= 1. Then do the definite integral of (x-x2) from X = 0 to X = 1, and get the answer of 1.

The second answer is y' = 3x2 (3 times the square of x), so the tangent slope k=3 times the square of 65438 +0 =3.

The slightly oblique tangent equation is y=3(x- 1)+ 1, that is, y=3x-2.