Y= 1 indicates a shot in a blue shot, and Y=0 indicates a shot; EY=3/4
(1) If Party A and Party B each throw 1 time, then X+Y represents the sum of their scores, and E (X+Y) = EX+EY = 2/3+3/4 =1712.
(2) The first two times A scored more than B, that is to say, in their two blue shots, A scored at the end of B, A scored twice at the end of B, and A scored twice at the end of B. These three events are independent of each other. So using binomial distribution, the probabilities are respectively P (once in A, once in B)+P (twice in A, twice in B)+P (once in A, twice in B) = 2 * (2/3) * (1/3) * (3/4) 2 +P(A 2.