∴∠BOC= 120,
Divide equally with OM ∠BOC,
∠COM= 12∠BOC=60,
∴∠con=∠com+90 = 150;
(2) prolonging NO,
∫∠BOC = 120
∴∠AOC=60,
When the straight line just bisects the acute angle ∠AOC,
∴∠AOD=∠COD=30,
That is, when rotating 300 clockwise, there is no extension line to bisect ∠AOC.
Judging from the meaning of the question, 10t = 300.
∴t=30,
When NO divides ∠AOC equally,
∴∠NOR=30,
That is, when rotating clockwise120, there is no bisection of ∠AOC.
∴ 10t= 120,
∴t= 12,
∴t= 12 or 30;
(3)∫∠MON = 90,∠AOC=60,
∴∠aom=90-∠ Aon, ∠NOC = 60-∠ Aon,
∴∠aom-∠noc=(90-∠aon)-(60-∠aon)= 30,
Therefore, the quantitative relationship between ∠AOM and ∠NOC is ∠ AOM-∠ NOC = 30.