∴∠BOC= 120，

Divide equally with OM ∠BOC,

∠COM= 12∠BOC=60，

∴∠con=∠com+90 = 150；

(2) prolonging NO,

∫∠BOC = 120

∴∠AOC=60，

When the straight line just bisects the acute angle ∠AOC,

∴∠AOD=∠COD=30，

That is, when rotating 300 clockwise, there is no extension line to bisect ∠AOC.

Judging from the meaning of the question, 10t = 300.

∴t=30，

When NO divides ∠AOC equally,

∴∠NOR=30，

That is, when rotating clockwise120, there is no bisection of ∠AOC.

∴ 10t= 120，

∴t= 12，

∴t= 12 or 30;

(3)∫∠MON = 90，∠AOC=60，

∴∠aom=90-∠ Aon, ∠NOC = 60-∠ Aon,

∴∠aom-∠noc=(90-∠aon)-(60-∠aon)= 30，

Therefore, the quantitative relationship between ∠AOM and ∠NOC is ∠ AOM-∠ NOC = 30.