Suppose equation 2X+(n? The two solutions of +2n-3)/(2X- 1)=2n+3 are X 1 and x2 (x 1 < x2) respectively.

Find (X2- 2 )/ (2X 1)

PS: It's for the convenience of viewing X 1,, X2.

You can:

X+ab/X=a+b

x？ -(a+b)x +ab=0

(x-a)(x-b)=0

x = a，x =b

2x +(n？ +2n-3)/(2x- 1)=2n+3

(2x- 1)+(n+3)(n- 1)/(2x- 1)=(n+3)+(n- 1)

2x- 1 = n+3 or 2x-1 = n- 1.

X = n/2 +2 or x = n/2.

(X2- 2 )/ (2X 1)

=(n/2 + 2 - 2)/(2* n/2)

=(n/2 )/ n

= 1/2