Answer (2,0)

B( 10，0)

C( 10，8)

d(2.8)

(2)

Because it is necessary to make a parabola through O, P and B, the analytical formula should be vertex-shaped.

(Vertex y = a (x-k) 2+ha is not zero.

Know that the vertex (k, h) and another point can be substituted to get a, and then you can get the analytical formula)

P(6，4)B( 10，0)

Substitute x, y, a, k and h to get a=- 1/4.

Analytical formula: y =- 1/4 (x-6) 2+4.

(3)

Let Q(x, y) pass through point q and make QE perpendicular to point e.

△QAB area =AB*QE/2=8*y/2= 16 to get y=4.

Substituting into the analytical formula gives x=6.

So point q and point p coincide.