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The fifth problem of finding the greatest common factor of the first volume of mathematics resources and learning plans in Beijing Normal University Edition
The first problem can be decomposed into: 5040=7×8×9× 10, and four numbers are obtained, which meets the conditions.

The second question and the first question have something in common and are also decomposed. The second question requires the same divisor, according to; Dividend = quotient × divisor+remainder

200= 196 + 4 = 2 × 98 + 4

300=294 + 6 = 3 × 98 + 6

500=490 + 10 = 5 × 98 + 10

Quotient 2, 3 and 5 are pairwise coprime, so the maximum number is 98.