If John, Peter and Rob sell X, Y and Z turkeys in the morning, they will sell 10-X, 16-Y and 26-Z turkeys in the afternoon. If the price is one pound in the morning and one pound in the afternoon, the following equation can be drawn from the meaning of the question:

ax+b( 10-x)=56 ①

ay+b( 16-y)=56 ②

az+b(26-z)=56 ③

This is an indefinite system of equations with five unknowns, but only three equations.

①-③ Get (x-z) (a-b) = 16b，④

②-③ Get (y-z) (a-b) = 10b，⑤

(x-z)/(y-z)=8/5, that is 5x+3z = 8y. ⑥.

According to the subject conditions, 0 < x < 10, 0 < y < 16, 0 < z < 26. After substituting into ⑥ test, we can find that only x=9, y=6, z= 1 is the only set of solutions, and then substitute into the values of X, Y and Z..

① and ② a=6 and b=2 can be calculated. So the price is 6 pounds each in the morning and 2 pounds each in the afternoon. John, Peter and Rob each sold 9,6 1 turkey in the morning and1,10,25 turkeys in the afternoon.

Chicken.

The problem of inheritance distribution:

The answer is that the inheritance of mother, son and daughter is X, Y and Z respectively, according to the meaning of the question.

X+Y+Z=3500 ①

X= 1/2Y ②

X=2Z ③

Y = 2x4from ②, z =1/2x5from ③, substitute ④ ⑤ into ①, X= 1000 into ④, Y=2000 into ⑤, and Z=500. Therefore, the inheritance of mother, son and daughter is 1000 respectively.