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Math problem: Six black balls, three white balls and five gray balls in grade four are arranged side by side. What color ball is No.2008? How many black balls were there in 2008? Urgent!
864

Six black balls, three white balls and five gray balls are arranged side by side, indicating a cycle 14 balls. 2008 divided by 14 equals 143.

That is to say, a * * * circulation 143 times six balls.

143×6=858 has 143 black balls.

The remaining six are the first six balls of a new cycle, and the first six balls of each cycle are black balls. So the remaining six balls are all black balls.

So there are 858+6=864 black balls.