Solution (1) m = 2; (2) The coordinate of c 2011is (2 20 10, and the ordinate is 2 20 10 * √ 3). The detailed explanation is as follows:

(1) From the title, we can know that △OB 1C 1∽△OB2C2, and the similarity ratio is m = ob2/ob1= oc1= 2.

(2) Ob 1 turn OC 1 once, turn 60 degrees, and the length is changed from1to 2. When it turned to OC6, it turned six times, exactly once, and the length changed from 1 to 2 6.

2011= 335 * 6+1,you can see that OB 1 turns to OC20 1 1 times, and turns 335 times to 60 degrees. The length of OB 1 is changed from 1 to oc201= 22011,that is, the point c 20 1 1 is in the first quadrant, and the edge oc20/. Therefore, the abscissa of point C20 1 1 *1/2 = 22010, and the ordinate is 2 20 1 1 * √ 3/2 =