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Creative clock face mathematics
1.

The fast clock is 3 minutes faster than the slow one every hour.

When displaying time, the fast clock is faster than the slow clock 1 hour =60 minutes.

So at this time, 60/3=20 hours have passed since the watch was taken away.

Because the fast clock is faster than the standard time 1 minute per hour.

So the standard time at this time should be 8: 40.

A watch from 20 hours ago, yesterday 10: 40.

2.

Let the commuting time be x.

Working hours are 1 1-3=8 hours or 480 minutes.

The time from home to home is

480+2x+ 10

The clock shows 8 hours and 50 minutes, that is, 530 minutes.

480+2x+ 10=530

X=20 means it takes 20 minutes to go to work.

Go to work from home to the factory at 3 o'clock, and there are still 10 minutes. So the departure time is 2: 30, which means 14: 30.

The watch stopped at 10/2, so it has stopped for 2 hours and 20 minutes, which is 140 minutes.

Because it may have stopped before 12 hour, 24 hours or 36 hours ..., it should be stopped accurately 12n*60+ 140 minutes (n is a natural number).