Suppose one number is 6X and the other number is 7y (both x and y are natural numbers).

therefore

6X+7Y=50

6X+6Y+Y=50

6(X+Y)=50-Y

So 50-Y must be a multiple of 6.

And 7Y

《

50

y \u

50/7(7 and 1/7)

Because y is a natural number, y can only be 0-7.

50-Y is a multiple of 6. 0-7, only 2 matches.

So Y=2

7Y= 14

So 6X=50-7Y=36 (qualified)

So it is divided into

36、 14

60 The same practice:

Suppose one number is 6X and the other number is 7y (both x and y are natural numbers).

therefore

6X+7Y=60

6X+6Y+Y=60

6(X+Y)=60-Y

So 60-Y must be a multiple of 6.

And 7Y

《

60

y \u

60/7(8 4/7)

Because y is a natural number, y can only be 0-8.

And 60-Y is a multiple of 6, and out of 0-8, only 6 matches.

So Y=6

7Y=42

So 6X=60-7Y= 18 (qualified)

So it is divided into

18、42