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Higher vocational mathematics examination paper
I don't know what Gauss-Jordan elimination is. Here's how to do it. I don't know if it is the so-called method

First of all, the first step is that I will eliminate X.

x+3y+2z=- 1

2x+3y+3z=-2

-2x+2y-3z=7

The first formula is multiplied by 2 2x+6y+4z=-2.

The second formula is 2x+3y+3z =-2.

Twice subtraction, left minus left minus right minus 3y+z=0.

The second formula 2x+3y+3z =-2.

The third formula -2x+2y-3z = 7.

Together, the two are the same, 5y=5, that is, y= 1.

Let y= 1 generation 3y+z=0 z=-3.

Then substitute y z into a formula and get x=2.