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A math problem that is neither simple nor difficult.
The one on the fourth floor startled me: on closer inspection, it turned out that the calculation was wrong.

2640*(9/20) = 1 188

1638 I don't know how to work it out.

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The production capacity of a factory:

Coat: 448/(8/ 15) = 840

Pants: 448/(7/ 15) = 960

Production capacity of factory b:

Coat: 720/(2/5) = 1800

Pants: 720/(3/5) = 1200

After the merger, suppose:

X (0

Y (0

Then, (coat = trousers = a set)

840 * x+ 1800 * y = 960 *( 1-x)+ 1200 *( 1-y)( 1)

840 * x+960 * x+ 1800 * y+ 1200 * y = 960+ 1200

1800 x+3000 x y = 2 160

The solution is y=( 18- 15*x)/25 (2).

Substitute to the left of (1)

840 * x+ 1800 *[( 18- 15 * x)/25]

=840*x+ 1296- 1080*x

= 1296-240*x

When x=0, the maximum number of sets is 1296.

At this time y= 18/25.

Factory:

Coat: 0

Pants: 960

Factory b:

Coat:1800 * (18/25) =1296

Pants: 1200*(7/25) = 336