2) ∠ b = 60, so when BP=2BQ or BQ=2BP, △PBQ must be a right triangle. Therefore, let 2X(s)=3-X(s) and get x (s) =1; Let 2[3-X(s)]=X(s), and X(s)=2 is obtained. That is, the answers are 1 and 2.

3)△BPQ area = bpx (3-AQ) x 0.5 √ 3 = X(s) x (3-x (s)) x 0.5 √ 3, so that △BPQ area =2.25√3 X 1/3=0.75√3, and x (.