=∫(0, 1) dx∫(0, 1–x)(3x+2y)dy
=∫(0, 1) dx (3xy+y? )|(0, 1–x)
=∫(0, 1)( 1+x–2x? )dx
=(x+x? /2–2 times? /3)|(0, 1)
= 1+ 1/2–2/3
=5/6