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A math problem in junior high school
(1) directly proves that triangle ABC is similar to triangle BCD without drawing.

It is proved that the similar process can deduce the relationship of angles according to the relationship of edges. These two triangles are isosceles triangles with a vertex angle of 36 degrees, that is, golden triangles.

AB:BC=BC:CD

CD=AC-AD=AB-BC

So AB:BC=BC:(AB-BC)

Solve equation BC=(3√5)-3.

(2) Yes ~ Because BC:AB=(AB-BC):BC, this is the definition of the golden section.

(3)AD=BC, in the Golden Triangle ABC, the ratio of BC to waist AC is the golden ratio, so

The ratio of AD to AC is also the golden section ratio, that is, D is the golden section point of AC.