I changed the letter of the original question, and the answer remains the same: the function y = cos (ω x+φ) (ω > 0, 0 < φ < π) is odd function, and some images of this function are given in the figure. A and B are the highest and lowest points respectively, and the distance between the two points is 2. Then the symmetry axis of this function is ().

Analysis: the function y = cos (ω x+φ) (ω > 0, 0 < φ < π) is odd function, and φ is found. As shown in the figure, A and B are the highest and lowest points respectively, and the distance between the two points is 2.

2. Find the period of the function, then find ω, and find the symmetric equation.

Solution: The function y = cos (ω x+φ) (ω > 0,0 < φ < π) is odd function, so φ = π/

2

Part of the image of this function is shown in the figure. A and B are the highest and lowest points respectively, and the distance between the two points is two symbols.

2

, so (2

Square root of 2

) 2=2 squared +(T/

2

) square,

So T=4, ω = π.

/2

, so the expression of the function is: y=-sin(π

/2)

X, obviously x= 1 is an equation of its symmetry axis.

Everyone is predestined friends, please adopt the answer.