Then satisfy 2i+j- 1=2m+n- 1, and i+j=m+n can be obtained from the monotonicity of the exponential function: when i+j≠m+n, aij≠amn, so the different values that this matrix element can get are all for I+J.
Solution: the element cij=ai in row I and column J of the matrix? aj+ai+aj =(2i- 1)(2j- 1)+2i- 1+2j- 1 = 2i+j- 1(I = 1,2,…,7; j= 1,2,…, 12),
If and only if: i+j=m+n, aij=amn(i, M = 1, 2, …, 7; j,n= 1,2,…, 12),
So the different values that matrix elements can get are the different sums of i+j, and the sums are 2, 3, …, 19, *** 18.
So choose a.
Please adopt O(∩_∩)O~ Oh if you are satisfied!