Substitute parabola y=-3/4x? In +mx+n, we can get {- 12-4m+n = 0 ① n =-3 ②.
∴m= 15/4 n=-3, and the analytical formula of∴ parabola is y=-3/4x? + 15/4x-3
Substituting a (4,0) into y=kx-3, you can get y=3/4x-3.
Let D(x, -3/4x? +15/4x-3), and the parallel lines with D as the Y axis intersect with AC and E,
∴E(x,3/4x-3),∴DE=-3/4x? + 15/4x-3-(3/4x-3)=-3/4x? +3 times
When x=-b/2a=-3/(-4/3)×2=2, then y =-3/2.
There is a point D(2, -3/2) on the parabola above the straight line CA, which makes the area of △ACD the largest.
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