Analysis: Starting from the second bit, each bit is 6 more than the previous bit, and the added phase is 6, so the nth bit is: 4+(n- 1) × 6 = 6n-2.

(2)2, 5, 10, 17 ... and find the nth digit.

Analysis: The rising rates of the series are 3, 5 and 7 respectively, and the rising rates increase by the same amount. Then, the increment from the number n- 1 to the number n is: 3+2×(n-2)=2n- 1, and the total increment is:

の3+(2n- 1)の×(n- 1)÷2 =(n+ 1)×(n- 1)= N2- 1

Therefore, the nth digit is: 2+ n2- 1= n2+ 1.

(3)0, 3, 8, 15, 24, … Try to write the number 100 times according to this rule.

Answer: 1002 1

(4)4, 16,36,64,? , 144, 196,… ? (hundredth digit)

Analysis: After dividing by 4, you can get a new series: 1, 4, 9, 16…, which is obviously the square of digits.

(5)2, 5, 10, 17, 26 ... Find the nth number.

According to the analysis and observation, the nth term of the new series is n2- 1, so the nth term of the series in the problem is: (N2- 1)+2 = N2+ 1.