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Mathematical problems about coordinates
Let q be: (a, 4a);

Then the slope k of DQ is 4 (1-a)/(6-a); Then the equation of DQ is: y-4 = k (x-6);

So the coordinates of m are: (5a/(a- 1), 0);

So when a person

When a> is at 1, the area of the triangle is: s =1/2 * 5 * a/(a-1) * 4 * a, and the equation has extreme values: X=2, S = 40.

When a= 1, the triangle area is: s =1/2 *1* 4 = 2;

Therefore, when a= 1, the triangle line area has a minimum value; At this time, the coordinate of q is (1, 4).