∴bc ∵ab⊥ac is the diameter of a circle.
AB=DE
The radius of the circle is also known.
So, in the right triangle ABC,
(I don't know the specific data) Find ∠ACB with trigonometric function, and then get ∠AOB.
Finally, the length of arc AB is calculated according to ∠AOB.
But you didn't give the whole question, and the lengths of AC and BE couldn't be found out.
If you get it, you can add the perimeter of the square to the perimeter of the circle, subtract the length of arc AB and the length of DE, AD and BE, and get the perimeter of the whole graph. The key is to be patient, hehe.
That's it, meow ~ ~ (handsome enough to be afraid of your love? It's very stingy to answer so many questions without giving you any wealth ~ ~ ~ yo ~ ~ heh ~ ~)