(1) If the current speed is x(km/h), then there is 240/ 10+x=240/8-x, and x=3, then the still water speed of passenger ship A from Port A to Port B is 24+3=27(km/h).

(2) According to the meaning of the question, the function relation can be set to y=(k+3)x, and when the distance between Party A and Party B is equal for the second time, 15h is needed, and (27+3) * (15-10) = (k+3) * 65433. = x & lt=240/ 10, which is 0.

(3) Let Party A and Party B be 20km apart at t(h), that is | (27+3) * (t-10)-/kloc-0 <| = 20,10.