The element of n is y, and the requirement for y is equal to the square of x- 1 >; =- 1, so n is a set greater than minus one, and the intersection of two sets is greater than minus one ~ ~ ~ m ∩ n = n

Question 2: If you solve m, it means that M={(x, y)÷3x-y-2 = 0 and x is not equal to 2}, and the condition of (x is not equal to 2) is easily ignored! ! ! ! It is not easy to find a big problem, but there are tricks to this small problem. . . ) so m and p are not equal.

And (CuM)∩P={(x, y)‖x=2, y∈R},

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