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A Math Problem about "One-dimensional Linear Inequality Group" (the second semester of Shenzhen Junior Two in Beijing Normal University) (the range of values)
(1) solving equations, x=-3+a, y=-4-2a.

X is a non-positive number and y is a negative number.

So x < =0, y<0.

So-3+a

-4-2a & lt; 0

sulphur dioxide

(2)a-3 & lt; =0

So when 2

When-2 < a <; 2. The original formula =3-a+(2-a)=5-2a.

(3)2ax+x & lt; 2x+ 1, that is, (2a-1) x; 1

So 2a- 1