Substitute x=-3, y=2, x= 1 and y=6 into the above formulas respectively, and obtain
2=-3k+b - ①
6=k+b - ②
②-① get 4k=4.
k= 1
Substitute k= 1 into ② to get b=5.
So the resolution function is: y=x+5.
② Let x=0, and you can get y = 5;; Let y=0 and x=-5.
Therefore, the required triangle area is
1/2×5×∣-5∣= 12.5
2.① Because the image of function y=(2m= 1)x+m-3 passes through the origin,
So, m-3=0, m=3.
② Because the image of function y=(2m= 1)x+m-3 does not pass through the second quadrant,
Therefore, 2m- 1 > 0, m-3≤0 ∴ 1/2≤m≤3.
Note: 1/2 is half.