∴EF parallel to BC
∴∠AEF=∠ABC
∠AFE=∠ACB
∴△AEF similarity and△△△ ABC
∴AK/AD=EF/BC
∫AK = AD-KD = AD-EG
∴AD-EG
/
advertisement
=EF
/
B.C.
8-EG
/
eight
=EF/ 10
EF= 10*(8-EG)
/
eight
Let EG be X.
10*(8-x)
/
8 *
x
=
15
The next step is to solve the equation.
Hope to adopt. Thank you.