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The answer to the sixth question on page 25 of the new mathematics classroom synchronous training in the sixth grade of People's Education Press,
The correct answer is that the hound must run at least 60 meters to catch up.

Solution:

From "the hound runs five steps and the rabbit runs nine steps", we can know that for every meter the hound walks, the rabbit walks 5/9 meters. According to "the hound can run 2 steps and the rabbit can run 3 steps", at the same time, the hound can run 2 meters and the rabbit can run 5/9 a * 3 = 5/3 a meters. From this, we can know that the speed ratio between the hound and the rabbit is 2A: 5/3A = 6: 5, that is to say, the hound runs 60 meters and the rabbit runs 50 meters, and the original difference of 10 meter is just used up.