The thickness of two layers of 300-grid toilet paper should be equal to the radius (r) of the whole roll of toilet paper-the radius (r) of the inner core of the paper tube, thus solving the equation.

Solution: Let the thickness of two layers of toilet paper be XM.

Then:1/kloc-0 /×1.4× x× 300 = π (5.82-2.32 )×1solution: x ≈ 0.026. Answer: Let the thickness of two layers of toilet paper be around 0.