The equation is better solved! Algebra, please!

Solution: the walking speed of people is X, the speed of trams is Y, and the distance between cars is equal.

Then it is: 4(x+y)= 12(y-x)

Solution: 2x=y

Reset: A tram leaves the starting station every t minutes.

Then it is: t*y=4(x+y) and the above formula are solved simultaneously.

Solution: t=6

Method 2:

Because trams are unified and the time between trams is excellent, the distance between trams is equal. Let the distance between trams traveling in the same direction be l, the speed of trams be V 1 and the speed of people be V2, then:

(V 1-V2)× 12=L

(V 1+V2)×4=L

Namely:

12V 1- 12V2=L

4V 1+4V2=L

Multiply both sides of the second formula by 3, and add it to the first formula to eliminate it:

24V 1=4L

L/V 1=6，

So the tram runs every six minutes.

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