Answer: Solution: ∵ According to the diagram, the coordinate of the intersection point A of a linear function and a quadratic function is (-2,0).
∴-2a+b=0,
∴b=2a.
∵ As can be seen from the figure, if the parabolic opening is upward, a > 0,
∴b>0.
The inverse proportional function image passes through the first and third quadrants,
∴k>0.
A, from the diagram, hyperbola is located in the first and third quadrants, then k > 0.
∴ 2a+k > 2a, that is, b < 2a+k 。
So this option is wrong;
b、∫b = 2a,
∴a=-k, then K.
∴k 0 is contradictory,
∴a=b+k is invalid.
So this option is wrong;
c、∫a > 0,b=2a,
∴b>a>0.
So this option is wrong;