∴A'C is the projection of A'B on aa' c' C surface.
Tan ∠ MAC = MC/AC = ∠ 2/2，Tan∠ACA′= A′A/AC =∠2。
∴tan∠mac*tan∠aca′= 1
∴∠mac+∠aca′=90
∴am⊥a′c
∴am⊥ba′
2. Certificate: According to the meaning of the question, there is BC⊥ face AA 'c 'c.
∴BC⊥AM
Conclusion in 1: AM⊥BA'
∴AM⊥ Noodles in BC
3. The meaning of this question is:
In the triangular pyramid M-ABC, MC⊥ plane ABC, ∠ ACB = 90, AC=√3, BC= 1, MC=√6/2.
The ∴ volume m-ABC V of a triangular pyramid = (BC * AC/2) * MC/3 = √ 2/4.
∴ Volume C-ABM V'=√2/4 of a triangular pyramid
According to the meaning of the question, AM=3√2/2, BM=√ 10/2, AB=2.
∴AB^2+BM^2=AM^2
The area of ∴△∴△abm is S=AB*BM/2=√ 10/2.
∴v′=s*h/3=(√ 10/6)h=√2/4
∴h=3√5/ 10
That is, the distance from point C to plane ABM is 3√5/ 10.
I will explain all this here. Of course, this is just my personal opinion. I hope it will help the landlord. . .